Q:

1. ) compare the amplitude of y=1.5sin(4x) to the amplitude of y=sin x2.) compare the period of y=1.5sin(4x) to the period of y=sinxplease help!​

Accepted Solution

A:
Figure is shown for graph of y=1.5sin4xThe equation of sin function is given as [tex]y=Asin(\frac{2\pi}{T} x )[/tex]Where A is Amplitude of function and T is Time periodGiven sin function is [tex]y=1.5sin(4x )[/tex]A) Compare the amplitude of y=1.5sin(4x) to the amplitude of y=sin xAnsIn y=sin x, Amplitude is 1 unit In y=1.5sin4x, Amplitude is 1.5 unit B) compare the period of y=1.5sin(4x) to the period of y=sinxIn y=sin x, Time period is[tex]\frac{2\pi}{T} x =x[/tex]T = [tex]2\pi[/tex]In y=1.5sin4x, Time period is[tex]\frac{2\pi}{T} x =4x[/tex][tex]T =\frac{2\pi}{4}[/tex][tex]T=\frac{\pi}{2}[/tex]C) Plot the graph for 2 periodShown in figure.