MATH SOLVE

5 months ago

Q:
# Write the equation of a line that is parallel to y = 0.62 +3 and that passes through the point (-3,-5).

Accepted Solution

A:

The equation of a line that is parallel to y = 0.62 x + 3 and that passes through the point (-3 , -5) is y = 0.62 x - 3.14Step-by-step explanation:Parallel lines have:1. Same slopes2. Different y-interceptThe slope-intercept form of the linear equation is y = m x + c, wherem is the slope of the line and c is the y-interceptWe need to find the equation of the line that is parallel to y = 0.62 x + 3 and passes through the point (-3 , -5)∵ The two lines are parallel∴ Their slopes are equal∵ The equation of the given line is y = 0.62 x + 3∵ The form of the equation is y = m x + c∴ m = 0.62∴ The slope of the line is 0.62∵ The equation of the line is y = mx + c∵ m = 0.62∴ The equation of the line is y = 0.62 x + c- To find c substitute x and y in the equation by the coordinates of a point lies on the line∵ The line passes through the point (-3 , -5)∴ x = -3 , y = -5∴ -5 = 0.62(-3) + c∴ -5 = -1.86 + c- Add 1.86 for both sides∴ c = -3.14∴ The equation of the line is y = 0.62 x + (-3.14)∴ The equation of the line is y = 0.62 x - 3.14The equation of a line that is parallel to y = 0.62 x + 3 and that passes through the point (-3 , -5) is y = 0.62 x - 3.14Learn more:You can learn more about linear equations in brainly.com/question/3965451#LearnwithBrainly